Without actually expanding how do you find the term independent of x in the expansion (2x-3/x^2) ^9? - Quora
The term independent of x in the binomial expansion of (1 - 1/x + 3x^5)(2x^2 - 1/x)^8 is : - Sarthaks eConnect | Largest Online Education Community
![SOLVED: 3 For the binomial expansion, in descending powers of x, of a) find the first 4 terms, simplifying each term: marks) b) find, in its simplest form; the term independent of SOLVED: 3 For the binomial expansion, in descending powers of x, of a) find the first 4 terms, simplifying each term: marks) b) find, in its simplest form; the term independent of](https://cdn.numerade.com/ask_images/f611725dfa04462c8df33760dacae715.jpg)
SOLVED: 3 For the binomial expansion, in descending powers of x, of a) find the first 4 terms, simplifying each term: marks) b) find, in its simplest form; the term independent of
![Find the term independent of x in the expansion of 〖〖(6x^2– 5/x^2 )]8. Binomial Theorem-Maths-Class-11 Find the term independent of x in the expansion of 〖〖(6x^2– 5/x^2 )]8. Binomial Theorem-Maths-Class-11](https://www.nextgurukul.in/media/images/q2aanswers/332/kk1_1391575512898.jpg)
Find the term independent of x in the expansion of 〖〖(6x^2– 5/x^2 )]8. Binomial Theorem-Maths-Class-11
The value of term independent of x in the expansion (2x^2 - 1/x)^12 - Sarthaks eConnect | Largest Online Education Community
![Find the term independent of x in the expansion of the following expressions: (1 + x + 2x^3) ( 32x^2 - 13x )^9 Enter 1 if answer is 1754 otherwise enter 0. Find the term independent of x in the expansion of the following expressions: (1 + x + 2x^3) ( 32x^2 - 13x )^9 Enter 1 if answer is 1754 otherwise enter 0.](https://haygot.s3.amazonaws.com/questions/1414669_1666828_ans_84978291b49d41e0989261119da4893b.jpg)
Find the term independent of x in the expansion of the following expressions: (1 + x + 2x^3) ( 32x^2 - 13x )^9 Enter 1 if answer is 1754 otherwise enter 0.
![Find the term independent of x in the expansion of the following binomials : ( (x)1/2/(3)1/2 - (3)1/2/2x )12 - Maths - Binomial Theorem - 14117457 | Meritnation.com Find the term independent of x in the expansion of the following binomials : ( (x)1/2/(3)1/2 - (3)1/2/2x )12 - Maths - Binomial Theorem - 14117457 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/discuss_editlive/2315393/2012_11_06_15_11_43/mathmlequation7305014821700023745.png)
Find the term independent of x in the expansion of the following binomials : ( (x)1/2/(3)1/2 - (3)1/2/2x )12 - Maths - Binomial Theorem - 14117457 | Meritnation.com
![Please solve as soon as possible QI 7 Find the term independent ofx in the expansion of (1 - Maths - Binomial Theorem - 13514703 | Meritnation.com Please solve as soon as possible QI 7 Find the term independent ofx in the expansion of (1 - Maths - Binomial Theorem - 13514703 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/content_ck_images/ck_5c81259d40683.png)
Please solve as soon as possible QI 7 Find the term independent ofx in the expansion of (1 - Maths - Binomial Theorem - 13514703 | Meritnation.com
![Additional Math - Binomial Theorem - No term independent of x ⋆ Tuition with Jason - Math Specialist Additional Math - Binomial Theorem - No term independent of x ⋆ Tuition with Jason - Math Specialist](https://www.tuitionwithjason.sg/wp-content/uploads/2020/05/feature-image-binomial-find-term-independent-og-x.png)